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Modular Exponentiation Algorithm

Overview​

Modular Exponentiation is an efficient algorithm for computing large powers modulo a number. This algorithm is widely used in cryptography and number theory, where dealing with large numbers is common, and directly calculating powers can lead to overflow. Instead of calculating base^exp first and then taking the modulo, modular exponentiation computes (base^exp) % mod efficiently using the exponentiation by squaring method, reducing the time complexity to logarithmic.

Problem Description​

  • Input: Three integers, base, exp, and mod, where:
    • base is the base number to be raised to the power.
    • exp is the exponent to which the base is raised.
    • mod is the number by which the result will be reduced.
  • Output: The result of (base^exp) % mod, calculated efficiently.
  • Constraints: Large values for base and exp make a direct approach infeasible, so modular exponentiation is necessary for efficiency.

Solution approach​

The modular exponentiation algorithm employs exponentiation by squaring, which reduces the problem size at each step by halving the exponent. This approach can be implemented recursively or iteratively and uses the following properties:

  • If exp is even: baseexp=(baseexp/2)2\text{base}^{\text{exp}} = (\text{base}^{\text{exp}/2})^2
  • If exp is odd: baseexp=base×(base(exp−1)/2)2\text{base}^{\text{exp}} = \text{base} \times (\text{base}^{(\text{exp}-1)/2})^2

At each step, the intermediate result is taken modulo mod to keep the numbers manageable.

Key Steps​

  1. Initialize the result to 1.
  2. Iterate while exp > 0:
    • If exp is odd, multiply result by base and take modulo mod.
    • Square the base and take modulo mod.
    • Divide the exponent by 2.
  3. Return the final result after the loop terminates.

Code Example​

def modular_exponentiation(base, exp, mod):
result = 1
base = base % mod # Update base if it's more than mod

while exp > 0:
if exp % 2 == 1: # If exp is odd
result = (result * base) % mod

base = (base * base) % mod # Square the base
exp //= 2 # Reduce exp by half

return result

# Example usage
result = modular_exponentiation(2, 10, 1000)
print(result) # Output: 24

Time Complexity​

The time complexity of the modular exponentiation algorithm is significantly reduced by the exponentiation by squaring technique.

Time Complexity Overview​

  • Time Complexity: O(log(exp))
    The algorithm reduces the exponent by half in each iteration, leading to a logarithmic number of steps relative to the size of the exponent. Each step involves constant-time operations like multiplication and modulo, so the overall time complexity is logarithmic.

Space Complexity​

  • Space Complexity: O(1)
    The space complexity is constant because only a few variables (such as base, exp, and result) are required to perform the computation.

Applications​

  • Cryptography: Modular exponentiation is heavily used in cryptographic algorithms such as RSA, Diffie-Hellman key exchange, and ElGamal.
  • Number Theory: Many problems in number theory, especially those related to prime numbers and modular arithmetic, rely on modular exponentiation.
  • Efficient Computation: This algorithm is used in any scenario where large powers need to be computed modulo a number without causing overflow or performance issues.

Conclusion​

The Modular Exponentiation Algorithm provides an efficient way to compute large powers modulo a number. It leverages the technique of exponentiation by squaring to reduce the number of operations from exponential to logarithmic time. This algorithm is crucial in fields like cryptography and number theory, where operations with large numbers are common and need to be performed efficiently.